How do you write an equation in slope-intercept form of the line that passes through the points (-3,3) and (1,2)?

Answer 1

#y=-1/4x+9/4#
The answer is written in slope-intercept form i.e. #y=mx+c#

#(x1,y1)=-(3,3)# #(x2,y2)=(1,2)# using equation two point slope-intercept form#y-y1=(y2-y1)/(x2-x1)(x-x1)# #(y-3)=(2-3)/(1+3)(x+3)# #y-3=-1/4(x+3)# #4(y-3)=-1(x+3)# #4y-12=-x-3# #4y=-x+9# #y=-1/4x+9/4#
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Answer 2

To write the equation in slope-intercept form, first, find the slope using the formula ( m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ). Then, use the slope and one of the given points in the form ( y = mx + b ) to solve for the y-intercept ( b ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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