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How do you write an equation in slope intercept form of a line containing the coordinates (-3,-6) with a slope of -4?

Answer 1

Eva Adamson

#y=-4x-18#

Point slope form of equation of a line with slope #m# and passing through #(x_1,y_1)# is

#(y-y_1)=mxx(x-x_1)#

In slope intercept form, equation is of the form #y=mx+c#

Thus, equation of a line passing through #(-3,-6)# and slope #-4# will be

#(y-(-6))=(-4)xx(x-(-3))#

or #(y+6)=(-4)xx(x+3)#

or #y+6==-4x-12#

In slope intercept form, it would be #y=-4x-18#

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Answer 2

Julia Adams

To write the equation of a line in slope-intercept form (y = mx + b), where m is the slope and b is the y-intercept, with a given point (-3, -6) and a slope of -4, substitute the values into the equation: y - y1 = m(x - x1). Then solve for y. Thus, the equation becomes y - (-6) = -4(x - (-3)). Simplify to get y + 6 = -4(x + 3). Distribute -4: y + 6 = -4x - 12. Subtract 6 from both sides: y = -4x - 18.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.