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How do you write an equation in slope intercept form given that the line passes through the point (2,7) and has a slope of 2?

Answer 1

Julia Adams

#y = 2x + 3#

First, write the equation in point-slope form:

Since we are given a point and the slope, we can plug them into the equation:
#y - 7 = 2(x-2)#

Now write it in slope-intercept form:

#y - 7 = 2x - 4#

Add #color(blue)7# to both sides:
#y - 7 quadcolor(blue)(+quad7) = 2x - 4 quadcolor(blue)(+quad7)#

#y = 2x + 3#

As you can see, this matches the slope-intercept form.

Hope this helps!

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Answer 2

Nathan Axel

To write an equation in slope-intercept form (y = mx + b) given a point and slope, you substitute the given slope for 'm' and the coordinates of the point for 'x' and 'y' in the equation, then solve for 'b', the y-intercept. Using the point (2,7) and a slope of 2, the equation becomes:

7 = 2(2) + b

Solving for 'b':

7 = 4 + b

b = 7 - 4 b = 3

Therefore, the equation in slope-intercept form is y = 2x + 3.

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Answer from HIX Tutor

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