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How do you write an equation in slope intercept form given (2,-3) & (-6,-7)?

Answer 1

#y=(x/2)-4#

Given two points are (2,-3) & (-6,-7) Equation of the line is written in the form, #(y-y1)/(y2-y1)=(x-x1)/(x2-x1)# #(y+3)/(-7+3)=(x-2)/(-6-2)# #-8(y+3)=-4(x-2)# #2y+6=x-2# #2y=x-8# #y=(x/2)-4# Where #m=(1/2)# and intercept #=-4#

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Answer 2

Kennedy Adams

To write an equation in slope-intercept form given two points ((2, -3)) and ((-6, -7)), first calculate the slope using the formula:

[m = \frac{y_2 - y_1}{x_2 - x_1}]

Substitute the given points into the formula:

[m = \frac{-7 - (-3)}{-6 - 2}]

[m = \frac{-7 + 3}{-6 - 2}]

[m = \frac{-4}{-8}]

[m = \frac{1}{2}]

Then, choose one of the points and substitute it along with the slope into the slope-intercept form equation (y = mx + b):

[y = mx + b]

[-3 = \frac{1}{2}(2) + b]

[-3 = 1 + b]

[b = -4]

Thus, the equation in slope-intercept form is (y = \frac{1}{2}x - 4).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

How do you write an equation in slope intercept form given (2,-3) &amp; (-6,-7)?

How do you write an equation in slope intercept form given (2,-3) & (-6,-7)?