How do you write an equation in slope intercept form for the line through the given point (5, -2) and (-16, 4)?
you can now insert this slope into the relationship:
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To write an equation in slope-intercept form for the line passing through the given points ((5, -2)) and ((-16, 4)), first find the slope (m) using the formula: [ m = \frac{y_2 - y_1}{x_2 - x_1} ] where ((x_1, y_1)) and ((x_2, y_2)) are the coordinates of the two points. Substituting the given points: [ m = \frac{4 - (-2)}{-16 - 5} ] [ m = \frac{6}{-21} ] [ m = -\frac{2}{7} ]
Now that we have the slope (m), we can use one of the points (let's use ((5, -2))) and the slope to write the equation in slope-intercept form ((y = mx + b)). Substituting (m = -\frac{2}{7}) and the point ((5, -2)): [ -2 = -\frac{2}{7}(5) + b ] [ -2 = -\frac{10}{7} + b ] [ b = -2 + \frac{10}{7} ] [ b = -\frac{14}{7} + \frac{10}{7} ] [ b = -\frac{4}{7} ]
Therefore, the equation of the line in slope-intercept form is: [ y = -\frac{2}{7}x - \frac{4}{7} ]
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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