How do you write an equation in point slope form that passes through (9,10) with slope -5?

Answer 1
In general, the point slope form of a linear equation is #color(white)("XXXX")##y-haty = m(x-hatx)# #color(white)("XXXX")##color(white)("XXXX")#where #m# is the slope #color(white)("XXXX")##color(white)("XXXX")#and #(hatx,haty)# is the point.
For a line passing through #(9,10)# with a slope of #(-5)# this is #color(white)("XXXX")##y-10 = (-5)(x-9)#
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Answer 2

To write an equation in point-slope form that passes through the point ((9, 10)) with a slope of (-5), you can use the point-slope form of a linear equation:

[y - y_1 = m(x - x_1)]

where ((x_1, y_1)) is the given point ((9, 10)) and (m) is the slope, which is (-5).

Substitute the values into the equation:

[y - 10 = -5(x - 9)]

Simplify:

[y - 10 = -5x + 45]

Now, add (10) to both sides:

[y = -5x + 45 + 10]

[y = -5x + 55]

This is the equation of the line in point-slope form that passes through ((9, 10)) with a slope of (-5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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