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How do you write an equation in point slope form that passes through (-2,-4),m=3/4?

Answer 1

Kennedy Adams

Equation of the line:# y = 3x/4 + b#

Find b by writing that this line passes at point (-2, -4)

#-4 = (3(-2))/4 + b -> b = -4 + 3/2 = -5/2#

y = 3x/4 - 5/2

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Answer 2

Avery Alexander

The point-slope equation is #y+4=3/4(x+2)#

The general equation for point-slope form is #y-y_1=m(x-x_1)# .

Given/Known:

Slope = #3/4#

Point = #(-2,-4)#

#x_1=-2# #y_1=-4#

Substitute the given/known values into the point-slope equation.

#y-y_1=m(x-x_1)# =

#y-(-4)=3/4(x-(-2))# =

#y+4=3/4(x+2)#

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Answer 3

Julia Adams

The equation in point-slope form is ( y - y_1 = m(x - x_1) ).

Given the point (-2, -4) and slope ( m = \frac{3}{4} ), the equation becomes:

[ y - (-4) = \frac{3}{4}(x - (-2)) ]

Simplify:

[ y + 4 = \frac{3}{4}(x + 2) ]

This is the equation in point-slope form.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.