How do you write an equation in point slope form given Point: (-2, 4); Slope: 5?
There is a very useful formula for the equation of a straight line if you have the slope and one point.
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The point-slope form of an equation of a line is given by:
y - y₁ = m(x - x₁)
where (x₁, y₁) represents a point on the line, and m represents the slope of the line.
Given the point (-2, 4) and the slope 5, the equation in point-slope form is:
y - 4 = 5(x + 2)
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
- How do you write the equation in point slope form given (4,3), slope -1/2?
- What is the slope of any line perpendicular to the line passing through #(29,36)# and #(57,30)#?
- How do you write the point slope form of the equation given (-4,1) parallel to #y=-1/2x-1#?
- What is the equation of the line between #(5,-6)# and #(2,-2)#?
- How do you write the slope-intercept form of the equation parallel to y = 7x + 2, which passes through the point (1, -3)?

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