How do you write an equation in point slope form given (–1, 3) and (1, 7)?

Answer 1

#y-7=2(x-1)#

#"the equation of a line in "color(blue)"point-slope form"# is.
#•color(white)(x)y-y_1=m(x-x_1)#
#"where m is the slope and "(x_1,y_1)" a point on the line"#
#"to calculate m use the "color(blue)"gradient formula"#
#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#
#"let "(x_1,y_1)=(-1,3)" and "(x_2,y_2)=(1,7)#
#rArrm=(7-3)/(1-(-1))=4/2=2#
#"use either of the 2 given points as a point on the line"#
#"using "(x_1,y_1)=(1,7)" then"#
#rArry-7=2(x-1)larrcolor(red)"in point-slope form"#
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Answer 2

I don't know what " point slope form" is but here's the equation
#y=2x+5#

If we have two points (-1,3) and (1,7) we can find the gradient (slope). We do this by finding the difference between the two #y# values and divide this by the difference between the two #x# values
7-3=4 this is the difference in the #y# values
1--1=1+1=2 #=># difference in #x# values
Gradient #=4/2# =2
The equation of the line is #y=2x+c# where the c value is the #y# intercept.( the place it crosses the #y# axis)

Substitute (1,7) into the equation to find c

7=#2xx1#+c

7=2+c

5=c

Put this into the equation in place of c

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Answer 3

To write an equation in point-slope form given two points, you first find the slope using the formula:

[ m = \frac{{y_2 - y_1}}{{x_2 - x_1}} ]

Then, you choose one of the points and the slope to plug into the point-slope form equation:

[ y - y_1 = m(x - x_1) ]

For the given points ((-1, 3)) and ((1, 7)), the slope (m) is:

[ m = \frac{{7 - 3}}{{1 - (-1)}} = \frac{4}{2} = 2 ]

Choosing the point ((-1, 3)) and substituting (x_1 = -1), (y_1 = 3), and (m = 2) into the point-slope form equation, we get:

[ y - 3 = 2(x - (-1)) ]

Simplify:

[ y - 3 = 2(x + 1) ]

[ y - 3 = 2x + 2 ]

[ y = 2x + 5 ]

Therefore, the equation in point-slope form is (y = 2x + 5).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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