How do you write an equation in point-slope form for the given (–3, –5) and (3, 0)?

Answer 1

The point-slope form is #y+5=5/6(x+3)#.

First determine the slope from the two points using the slope equation #m=(y_2-y_1)/(x_2-x_1)#, where #m# is the slope and #(x_1,y_1)# and #(x_2,y_2)# are the two points.
#(x_1,y_1)=(-3,-5)#
#(x_2,y_2)=(3,0)#
#m=(y_2-y_1)/(x_2-x_1)#
#m=(0-(-5))/(3-(-3))# =
#m=5/6#
Now use the slope and one point in order to write the linear equation in point-slope form. The general equation for the point-slope form is #y-y_1=m(x-x_1)#. where #m# is the slope and #(x_1,y_1)# is one of the two points.

#m=5/6

Point=#(-3,-5)#
#y-y_1=m(x-x_1)#
#y-(-5)=5/6(x-(-3))# =
#y+5=5/6(x+3)#
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Answer 2

To write an equation in point-slope form for the given points (-3, -5) and (3, 0), you first calculate the slope using the formula: (m = \frac{{y_2 - y_1}}{{x_2 - x_1}}). Then, choose one of the points and plug the coordinates and the slope into the point-slope form equation: (y - y_1 = m(x - x_1)). So, the equation would be (y + 5 = \frac{1}{2}(x + 3)).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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