How do you write an absolute value equation that could be used to express the distance from point P to the origin is 5 more than twice the value of P?

Answer 1
The answer is: #abs(x) = 2x+5#

Given:

#P# is a point on the #x#-axis.
The distance between the origin and #P# is #5# more than twice of the value of #P#

Absolute value operator gives us the distance from any point to the origin.

For example:

#abs(5) = abs(-5) = 5#
Lets say that #P# is #(x,0)#
The distance from point #P# to origin is:
#(x,0) - (0,0) = 2x+5#
#(x,0) - (0,0) -= abs(PO)#

So the result is:

#abs(x) = 2x+5#
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Answer 2

The absolute value equation to express the distance from point P to the origin as 5 more than twice the value of P is:

|P| = 2P + 5

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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