How do you write a direct variation equation that passes through the point (5,-6)?
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To write a direct variation equation passing through the point (5, -6), use the formula ( y = kx ), where ( k ) is the constant of variation. To find ( k ), substitute the given point's coordinates into the equation and solve for ( k ).
Given the point (5, -6), substitute ( x = 5 ) and ( y = -6 ) into the equation:
( -6 = k \times 5 )
Now, solve for ( k ):
( k = \frac{-6}{5} )
Thus, the direct variation equation passing through the point (5, -6) is ( y = -\frac{6}{5}x ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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