How do you write a direct variation equation that passes through the point (5,-6)?

Answer 1
A direct variation equation is of the form #y = m*x# for some constant value #m#
For a direct variation equation passing through #(x,y) = (5,-6)# we have #-6 = m*(5)# #rarr m = -6/5# and the direct variation equation is #y = (- 6/5)x#
which you might re-write as #5y = -6x#
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Answer 2

To write a direct variation equation passing through the point (5, -6), use the formula ( y = kx ), where ( k ) is the constant of variation. To find ( k ), substitute the given point's coordinates into the equation and solve for ( k ).

Given the point (5, -6), substitute ( x = 5 ) and ( y = -6 ) into the equation:

( -6 = k \times 5 )

Now, solve for ( k ):

( k = \frac{-6}{5} )

Thus, the direct variation equation passing through the point (5, -6) is ( y = -\frac{6}{5}x ).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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