# How do you write a balanced nuclear equation for alpha decay of Po-218?

Here's how you can do that.

When a radioactive nuclide undergoes alpha decay, it emits an *alpha particle*,

This means that after the alpha particle is emitted

the mass number of the nuclide will decrease by#4# #-># this happens because the alpha particle contains#2# protons and#2# neutronsthe atomic number of the nuclide will decrease by#2# #-># this happens because the alpha particle contains#2# protons

You can thus say that you have

#""_ (color(white)(.)84)^218"Po" -> ""_ (color(white)(.)(84-2))^((218 - 4))"X" + ""_ 2^4alpha#

A quick look in the Periodic Table of Elements will show that the element that has the atomic number equal to

#84 - 2 = 82 -># conservation of charge

is lead,

#218 - 4 = 214 -># conservation of mass

The balanced nuclear equation that describes the alpha decay of polonium-218 will look like this

#""_ (color(white)(.)84)^218"Po" -> ""_ (color(white)(.)82)^214"X" + ""_ 2^4alpha#

As

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*Answer 2Sign up to view the whole answerSign up with email*[_{84}^{218}\text{Po} \rightarrow ,_2^4\text{He} + ,_82^{214}\text{Pb}]

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*Answer from HIX Tutor**When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.*

*When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.*

*When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.*

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