How do you write #9.056 times 10^-4# in standard notation?

Answer 1

#9.056xx10^(-4)=0.0009056#

In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of #10#.

In other words, in scientific notation, a number is written as #axx10^n#, where #1<=a<10# and #n# is an integer and #1<=a<10#.

To write the number in normal or standard notation one just needs to multiply by the power #10^n# (or divide if #n# is negative). This means moving decimal #n# digits to right if multiplying by #10^n# and moving decimal #n# digits to left if dividing by #10^n# (i.e. multiplying by #10^(-n)#).

In the given case, as we have the number as #9.056xx10^(-4)#, we need to move decimal digit to the left by four points. For this, let us write #4.5# as #00009.056# and moving decimal point four points to left means #0.0009056#

Hence in standard notation #9.056xx10^(-4)=0.0009056#

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Answer 2

Levi Adams

[ 9.056 \times 10^{-4} = 0.0009056 ]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.