How do you write #9.002 times 10^-5 # in standard notation?

Question

Mila Anderson · Accepted Answer

#0.00009002# #9.002 xx 10^-5# #=9 2/1000 xx 1/100000# #=9002/1000 xx 1/100000# #=9002.0/100000000# Move the eight places to the left of the decimal point. #=0.00009002#

Emery Allen · Answer

In standard notation #9.002xx10^(-5)=0.00009002# In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of #10#. In other words, in scientific notation, a number is written as #axx10^n#, where #1<=a<10# and #n# is an integer and #1<=a<10#. To write the number in normal or standard notation one just needs to multiply by the power #10^n# (or divide if #n# is negative). This means moving decimal #n# digits to right if multiplying by #10^n# and moving decimal #n# digits to left if dividing by #10^n# (i.e. multiplying by #10^(-n)#). In the given case, as we have the number as #9.002xx10^(-5)#, we need to move decimal digit to the left by five points. For this, let us write #9.002# as #000009.002# and moving decimal point five points to left means #0.00009002# Hence in standard notation #9.002xx10^(-5)=0.00009002#

Skylar Adams · Answer

undefined 9.002 times $10^{-5}$ in standard notation is $0.00009002$.

Cameron Arnold · Answer

undefined 9.002 times 10^-5 in standard notation is 0.00009002.