# How do you write 720 as a product of its prime factors?

You can do the "ladder method"of continuous short division, making sure that you only divide by prime numbers.

I prefer to just use 2 factors to start with and then split the factors again and again until they are all primes.

This method is quick, easy and effective, but it requires a solid knowledge of the times tables.......

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You can start with any pair and you will end up with the same result.

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Finding all the prime numbers that, when multiplied together, equal the number is the first step in writing any number as the product of its prime factors. It should be noted that prime numbers may be repeated in this type of factorization; what matters is that

(1) Every number is prime.

(2) and a number is assigned to their product

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The prime factorization of 720 is ( 2^4 \times 3^2 \times 5 ).

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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