How do you write #(6 times 10^6) ÷ (8 times 10^3)# in standard form?

Answer 1

#7.5xx10^2#

If dividing a greater value into a lesser value is giving you a problem do this:

#6xx10^6" is the same as "60xx10^5#
So we have #(60xx10^5)-:(8xx10^3)#
#60/8xx10^5/10^3#
#60/8xx10^(5-3)#
#60/8xx10^2# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ By calculator we have: #7.5xx10^2# ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ I sort of cheat for the division #60/8#
#5xx8=40# but to give us 60 we need 20 more.
Note that #1/2# of #40=20#
#color(white)("dddd")5xx8=40color(white)("dddd") -> color(white)("dddd")5xx8=40# #1/2xx5xx8=1/2xx40->color(white)("ddd")2 1/2xx8=20#
So #ubrace((2 1/2+5))xx8=40+20=60#
#color(white)("dddddd")7.5 color(white)("d")xx8=60#
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Answer 2

To write ((6 \times 10^6) ÷ (8 \times 10^3)) in standard form, you divide the coefficients and subtract the exponents of 10.

This simplifies to (0.75 \times 10^{6-3}), which is (0.75 \times 10^3). In standard form, this is written as (7.5 \times 10^2).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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