How do you write #5x-y=1 # into slope intercept form?

Answer 1

#y=5x-1#

Slope intercept form can be represented as #y=mx +b# To get an equation into this form, we should try to get #y# all alone.
From #5x-y=1# first, we can add #y# to both sides and get #5x = y+1# then, we can subtract #1# from both sides to get #=> y=5x-1# which is now in slope intercept form :)
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Answer 2

To write the equation (5x - y = 1) in slope-intercept form (y = mx + b):

  1. Subtract (5x) from both sides: (-y = -5x + 1).
  2. Divide both sides by (-1) to isolate (y): (y = 5x - 1). So, the equation (5x - y = 1) in slope-intercept form is (y = 5x - 1).
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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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