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How do you write #(5k + 2)(3k + 1)# in standard form?

Answer 1

Genesis Allen

#15k^2 + 11k + 2#

Use FOIL, or in other words, distribute the terms in the first parenthesis to the terms in the second parenthesis.

So this would be: #(5k + 2)(3k + 1)#

#5k(3k) + 5k(1) + (2)(3k) + 2(1)# #15k^2 + 5k + 6k +2# #15k^2 + 11k +2#

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Answer 2

Nathan Axel

To write (5k + 2)(3k + 1) in standard form, you distribute each term in the first expression by each term in the second expression and then combine like terms. The result is:

(5k + 2)(3k + 1) = 15k^2 + 5k + 6k + 2 = 15k^2 + 11k + 2

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.