How do you write #5+3x# in standard form?

Answer 1
#x=-5/3#
#5+3x=0#
#3x=-5#
#x=-5/3#

This should be pretty self-explanatory ;)

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Answer 2
In standard form #5+3x# is #3x+5#.

The convention is to gather the highest order terms together first followed by the next highest order, down to any constant term.

For example, #2+6x^2y^2-3x^3# would be written as:
#6x^2y^2-3x^3+2#
The order of the first term is #2+2 = 4#, the next #3# and the order of the constant term is #0#.
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Answer 3

To write 5 + 3x in standard form, you simply arrange the terms in descending order of their exponents. So, it would be written as 3x + 5.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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