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How do you write #4y = 3/16x - 0.8# in standard form?

Answer 1

Problem: Write #4y=3/16x-0.8# in standard form.

Since you have two different variables, I'm going to answer this question as if you want to know how to write the given equation as a linear equation in standard form, Ax+By=C.

Subtract #3/16x# from both sides of the equation.

#-3/16x+4y=-0.8#

Multiply times #-1#.

#3/16x-4y=0.8#

Multiply both sides by #16#.

#3x-64y=12.8#

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Answer 2

Julia Adams

To write 4y = \frac{3}{16}x - 0.8 in standard form:

Multiply both sides by 16 to clear the fraction:

16 * 4y = 16 * \frac{3}{16}x - 16 * 0.8

64y = 3x - 12.8

Rearrange to get all terms on one side:

3x - 64y = 12.8

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.