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How do you write #4x=8y-12# in standard form and what is A, B, C?

Answer 1

Avery Alexander

#4x-8y=-12#

#"the equation of a line in "color(blue)"standard form"# is.

#color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))#

#"where A is a positive integer and B, C are integers"#

#"given "4x=8y-12#

#"subtract 8y from both sides"#

#>4x-8y=cancel(8y)cancel(-8y)-12#

#rArr4x-8y=-12larrcolor(blue)"in standard form"#

#"with "A=4,B=-8" and "C=-12#

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Answer 2

Hazel Anglin

To write the equation (4x = 8y - 12) in standard form, we need to rearrange it so that all the variables are on one side and the constant term is on the other side.

Starting with (4x = 8y - 12), we can move the (8y) term to the left side by subtracting (8y) from both sides:

[4x - 8y = -12]

To make the coefficients integers, we can divide all terms by their greatest common divisor, which in this case is 4:

[\frac{4x}{4} - \frac{8y}{4} = \frac{-12}{4}] [x - 2y = -3]

So, the equation in standard form is (x - 2y = -3). In this form, (A = 1), (B = -2), and (C = -3).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.