Home > Algebra > Vertex Form of a Quadratic Equation

How do you write #3x(10-4x)-6(x=5)+15# in standard form?

Answer 1

Eli Assouline

#-4x^2 + 8x - 15 = 0#

#ax^2 + bx + c = 9#is the standard form of quadratic equation.

Removing braces,

#30x -12x^2 -6x = 30 + 15#

#-12x^2 + 24x = 45#

#-12x^2 + 24x -45 = 0 #

dividing both sides by 3,

#-4x2 + 8x -15 = 0#

By signing up, you agree to our Terms of Service and Privacy Policy

Answer 2

Eva Adamson

To write the expression ( 3x(10 - 4x) - 6(x - 5) + 15 ) in standard form, you first distribute the terms and then combine like terms:

( 3x(10 - 4x) - 6(x - 5) + 15 )

( = 30x - 12x^2 - 6x + 30 + 15 )

( = -12x^2 + 24x + 45 )

So, the expression in standard form is ( -12x^2 + 24x + 45 ).

By signing up, you agree to our Terms of Service and Privacy Policy

Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.