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How do you write #(-3x-1)(x+1)# in standard form?

Answer 1

#-3x^2 - 4x - 1 #

multiply out the brackets. Each term in the 2nd bracket must be multiplied by each term in the 1st. To ensure this happens set out as follows :

#-3x(x + 1 ) - 1(x + 1 )#

# = -3x^2 - 3x - x - 1 = -3x^2 - 4x - 1 #

Standard form is writing the expression , starting with the term that has the highest power of the variable followed by terms with decreasing powers until the last term , usually a constant.

# a_n x^n + a_(n-1) x^(n-1) + a_(n-2) x^(n-2) + ...... + a_0 x^0#

hence : #-3x^2 - 4x - 1 " is in standard form " #

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Answer 2

Jameson Allen

To write (-3x-1)(x+1) in standard form, you need to multiply the two binomials using the distributive property and then combine like terms.

(-3x - 1)(x + 1) = -3x(x) - 3x(1) - 1(x) - 1(1) = -3x^2 - 3x - x - 1 = -3x^2 - 4x - 1

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.