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How do you write #2x^2 - 3 = -6x - 2# in standard form?

Answer 1

Isaiah Anthony

#2x^2 +6x-1=0#

Standard form of a quadratic equation looks like this: #ax^2 + bx + c = 0#

So basically, we need one side of the equation to be #0#.

#2x^2-3=-6x-2#

add everything to the left side #2x^2-3+6x+2=0#

simplify #2x^2 +6x-1=0#

usually you want #a# (which is #2# in this case) to be positive, and it is so we are done.

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Answer 2

Avery Alexander

To write the equation (2x^2 - 3 = -6x - 2) in standard form, you would rearrange the terms so that all terms are on one side of the equation and the terms are ordered in descending powers of x. The standard form of a quadratic equation is (ax^2 + bx + c = 0), where (a), (b), and (c) are constants.

To convert (2x^2 - 3 = -6x - 2) to standard form, you would add (6x) to both sides to eliminate the (x) term on the right side, and add 3 to both sides to eliminate the constant term on the left side. This results in the equation (2x^2 + 6x + 1 = 0).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.