How do you write #-2(x-3)(x+1)# in vertex form and identify the vertex, y intercept and x intercept?
y = - 2(x - 3)(x + 1)
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To write (-2(x-3)(x+1)) in vertex form, you first expand it to (-2(x^2 - 2x - 3)), then complete the square to get (-2(x - 1)^2 + 4). The vertex is (1, 4). The y-intercept is found by setting (x = 0), giving a y-value of -6. The x-intercepts are found by setting (y = 0) and solving for x, giving x-values of 1 and -3.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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