How do you write #-2(x-3)(x+1)# in vertex form and identify the vertex, y intercept and x intercept?

Answer 1

y = - 2(x - 3)(x + 1)

The 2 x-intercepts are: x1 = 3 and x2 = - 1 To find y-intercept, make x = 0 -> y = - 2(-3)(1) = 6 x coordinate of vertex:# x = (x1 + x2)/2 = (3 - 1)/2 = 1# y coordinate of vertex: y = f(1) = - 2(-2)(2) = 8
Vertex form #y = -2(x - 1)^2 + 8#
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Answer 2

To write (-2(x-3)(x+1)) in vertex form, you first expand it to (-2(x^2 - 2x - 3)), then complete the square to get (-2(x - 1)^2 + 4). The vertex is (1, 4). The y-intercept is found by setting (x = 0), giving a y-value of -6. The x-intercepts are found by setting (y = 0) and solving for x, giving x-values of 1 and -3.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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