# How do you write #-2(x-3)(x+1)# in vertex form and identify the vertex, y intercept and x intercept?

y = - 2(x - 3)(x + 1)

By signing up, you agree to our Terms of Service and Privacy Policy

To write (-2(x-3)(x+1)) in vertex form, you first expand it to (-2(x^2 - 2x - 3)), then complete the square to get (-2(x - 1)^2 + 4). The vertex is (1, 4). The y-intercept is found by setting (x = 0), giving a y-value of -6. The x-intercepts are found by setting (y = 0) and solving for x, giving x-values of 1 and -3.

By signing up, you agree to our Terms of Service and Privacy Policy

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

- The square of Jamie's age now is equals to his age in 6 years time. How old is Jamie now?
- What is the vertex form of the equation of the parabola with a focus at (2,-29) and a directrix of #y=-23#?
- How do you find the roots, real and imaginary, of #y= -3x^2-16x +(x-3)^2+2 # using the quadratic formula?
- How do you find the axis of symmetry, vertex and x intercepts for #y=3x^2+12x+5#?
- How do you find the solution to the quadratic equation #x^4 -3x^2 -4= 0#?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7