How do you write #-2-(-16)# as a single integer?

Answer 1

Alright, the first step here is we see that there are two negatives together (next to each other). From a theorem, we know that this also means that these two numbers are equal

#-2-(-16)=-2+16#

Now this becomes a relatively simple question. We cant forget the "#-#" sign in front of the #2# though!

#-2+16=14#

Hope that helps! ~Chandler Dowd

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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