How do you write #12times 10^-6# in standard form?

Answer 1

#12xx10^(-6)=0.000012#

In scientific notation, we write a number so that it has single digit to the left of decimal sign and is multiplied by an integer power of #10#.
In other words, in scientific notation, a number is written as #axx10^n#, where #1<=a<10# and #n# is an integer and #1<=a<10#.
To write the number in normal or standard notation one just needs to multiply by the power #10^n# (or divide if #n# is negative). This means moving decimal #n# digits to right if multiplying by #10^n# and moving decimal #n# digits to left if dividing by #10^n# (i.e. multiplying by #10^(-n)#).
In the given case, as we have the number as #12xx10^(-6)#, we need to move decimal digit to the left by six points. For this, let us write #12# as #00000012# and moving decimal point six points to left means #0.000012#
Hence in standard notation #12xx10^(-6)=0.000012#
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Answer 2

To write (12 \times 10^{-6}) in standard form, you move the decimal point six places to the left because of the negative exponent. This gives (0.000012). Therefore, (12 \times 10^{-6}) in standard form is (0.000012).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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