# How do you verify this? sin(x) cos(x) [tan(x) + cot(x)] = 1 Thank you!!

In the description

By signing up, you agree to our Terms of Service and Privacy Policy

To verify the equation sin(x) cos(x) [tan(x) + cot(x)] = 1, we can use trigonometric identities. First, we rewrite tan(x) and cot(x) in terms of sin(x) and cos(x):

tan(x) = sin(x) / cos(x) cot(x) = cos(x) / sin(x)

Then, substitute these expressions into the equation:

sin(x) cos(x) [tan(x) + cot(x)] = sin(x) cos(x) [sin(x)/cos(x) + cos(x)/sin(x)]

Next, simplify the expression:

= sin(x) cos(x) [(sin(x))^2 / (cos(x)) + (cos(x))^2 / (sin(x))]

= sin(x) cos(x) [(sin^2(x) + cos^2(x)) / (sin(x) cos(x))]

Using the Pythagorean identity sin^2(x) + cos^2(x) = 1:

= sin(x) cos(x) [1 / (sin(x) cos(x))]

= 1

Therefore, sin(x) cos(x) [tan(x) + cot(x)] equals 1, verifying the equation.

By signing up, you agree to our Terms of Service and Privacy Policy

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7