How do you verify that the hypotheses of rolles theorem are right for #f(x)= x sqrt(x+2)# over the interval [2,4]?

Answer 1

The hypotesis of the Rolles theorem are:

If the hypotesis are satisfied, than there is a point #P(c,f(c))# such as #a < b < c# in which:
#f'(c)=0#.
Our function has domain #[-2,+oo]# (the radicand has to be positive or zero): so the function is continue in #[2,4]#.

The derivative is:

#y'=1*sqrt(x+2)+x*1/(2sqrt(x+2))#
and its domain is #(-2,+oo)#, because the root has gone at the dominator so the radicand has to be only positive: so the functionis derivable in #(2,4)#.

So the theorem can't be applicated!

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Answer 2

To verify that the hypotheses of Rolle's Theorem are satisfied for ( f(x) = x \sqrt{x + 2} ) over the interval ([2, 4]), follow these steps:

  1. Check Continuity: Verify that ( f(x) ) is continuous on the closed interval ([2, 4]).

  2. Check Differentiability: Confirm that ( f(x) ) is differentiable on the open interval ((2, 4)).

  3. Check Endpoints: Ensure that ( f(2) = f(4) ).

  4. Calculate Derivative: Find the derivative of ( f(x) ), denoted as ( f'(x) ).

  5. Find Critical Point: Determine if there exists a point ( c ) in the open interval ((2, 4)) such that ( f'(c) = 0 ).

  6. Verify Hypotheses: Confirm that all conditions are met. If all conditions are satisfied, then Rolle's Theorem is applicable.

  7. Conclusion: If all conditions are met, conclude that there exists at least one ( c ) in the open interval ((2, 4)) such that ( f'(c) = 0 ), implying that there exists a point ( c ) in the open interval ((2, 4)) such that ( f'(c) = 0 ).

  8. Additional Note: Rolle's Theorem guarantees the existence of at least one point ( c ) in the open interval ((2, 4)) such that the derivative of ( f(x) ) is zero, given that the function meets the specified criteria.

If all steps are successfully completed, the hypotheses of Rolle's Theorem are verified for ( f(x) = x \sqrt{x + 2} ) over the interval ([2, 4]).

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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