How do you verify if h=-5 is a solution to #4h> -12#?
Not a solution.
Exchange h by -5 and see if it's true or false.
False
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To verify if h = -5 is a solution to 4h > -12, substitute -5 for h and check if the inequality holds true. In this case, 4(-5) > -12 becomes -20 > -12, which is true. Therefore, h = -5 is a solution to 4h > -12.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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