How do you use the quadratic formula to find both solutions to the quadratic equation #(2y - 3) (y + 1) = 5#?
Multiply out and rearrange into the form
This has solutions given by the quadratic formula:
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To use the quadratic formula to find both solutions to the quadratic equation (2y - 3)(y + 1) = 5, first expand the left side of the equation and rearrange it into the standard quadratic form ax^2 + bx + c = 0. After that, identify the values of a, b, and c. Then, substitute these values into the quadratic formula: x = (-b ± √(b^2 - 4ac)) / (2a). Finally, solve for the values of y using the formula.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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