# How do you use the quadratic formula to find both solutions to the quadratic equation #x^2-3x=-10#?

Solve

There are no real roots. There are 2 complex roots.

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To use the quadratic formula, which is ( x = \frac{{-b \pm \sqrt{{b^2 - 4ac}}}}{{2a}} ), for the quadratic equation ( x^2 - 3x = -10 ), you need to identify ( a ), ( b ), and ( c ) from the equation ( ax^2 + bx + c = 0 ). In this case, ( a = 1 ), ( b = -3 ), and ( c = -10 ). Substitute these values into the quadratic formula and solve for ( x ). You'll get two solutions.

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