How do you use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by #y=x^2#, y=2-x x=0 revolved about the y-axis?
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To use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by (y=x^2), (y=2-x), and (x=0) revolved about the y-axis, follow these steps:
- Determine the limits of integration by finding the points of intersection between the curves (y=x^2) and (y=2-x).
- Set up the integral to find the volume using the formula for cylindrical shells: [V = 2\pi \int_a^b x \cdot h(x) , dx], where (h(x)) represents the height of the shell at each value of (x), and (a) and (b) are the limits of integration.
- Calculate (h(x)) by finding the difference between the upper and lower functions at each (x) value.
- Evaluate the integral using the determined limits of integration and the calculated (h(x)) function.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you find the volume of the solid generated by revolving the region bounded by the curves y = x² and y =1 rotated about the y=-2?
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