How do you use the intercepts to graph #-x+4y=8#?

Question

Kennedy Adams · Accepted Answer

You only need two points to draw a line graph,therefore, compute the intercepts #(-8, 0)# and #(0, 2)# then connect the two points.

From the given equation #-x+4y=8#, just set one variable to zero at a time then solve for the numerical value of the other. Let us do it #-x+4y=8# Set #y=0" "#and then substitute that value in the equation #-x+4(0)=8# #-x+0=8# #-x=8# #(-x)/(-1)=8/(-1)# and #x=-8# this means there is a point on the line at #(-8, 0)# Now set #x=0# and then substitute that value in the equation #-(0)+4y=8# #0+4y=8# #4y=8# #(4y)/4=8/4# #y=2# this means there is another point on the line at #(0, 2)# Now, to graph the #-x+4y=8#, you only need to draw a line from #(-8, 0)# to #(0, 2)# Kindly see the graph of #-x+4y=8# and check the two points we calculated. graph{-x+4y=8[-20,20,-10,10]} God bless...I hope the explanation is useful.

Avery Alexander · Answer

undefined To graph the equation -x + 4y = 8 using intercepts, first find the x-intercept by setting y = 0 and solving for x:
-x + 4(0) = 8
-x = 8
x = -8
So, the x-intercept is (-8, 0).
Next, find the y-intercept by setting x = 0 and solving for y:
-0 + 4y = 8
4y = 8
y = 2
So, the y-intercept is (0, 2).
Plot these intercept points on the coordinate plane and draw a straight line passing through them to represent the graph of the equation.