How do you use the important points to sketch the graph of #F(x)=3x^2+4x-1 #?
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To sketch the graph of ( F(x) = 3x^2 + 4x - 1 ), you can follow these steps:
- Determine the vertex of the parabola using the formula ( x = -\frac{b}{2a} ).
- Find the y-coordinate of the vertex by substituting the x-coordinate into the function.
- Locate the y-intercept by setting ( x = 0 ) and solving for ( y ).
- Find the x-intercepts by solving the quadratic equation ( 3x^2 + 4x - 1 = 0 ).
- Plot these points on a coordinate plane.
- Determine the direction of the parabola by examining the coefficient of ( x^2 ) (positive coefficient means the parabola opens upwards, negative coefficient means it opens downwards).
- Sketch the parabola passing through the plotted points, making sure it is symmetric around the axis of symmetry.
These steps will help you sketch the graph of the given quadratic function.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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- How do you use the important points to sketch the graph of #f(x) = -7(x - 2)^2 - 9#?
- How do you write the quadratic in vertex form given #y=1/2(x-3)^2+8#?

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