How do you use the Fundamental Theorem of Calculus to find the derivative of #int e^(4t²-t) dt# from 3 to x?
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To find the derivative of the integral ( \int_{3}^{x} e^{4t^2 - t} , dt ), you can use the Fundamental Theorem of Calculus. The Fundamental Theorem of Calculus states that if ( F(x) ) is the antiderivative of ( f(x) ), then ( \int_{a}^{x} f(t) , dt = F(x) - F(a) ).
In this case, ( f(t) = e^{4t^2 - t} ). To find the antiderivative ( F(x) ), integrate ( f(t) ) with respect to ( t ):
[ F(x) = \int e^{4t^2 - t} , dt ]
After finding ( F(x) ), you can differentiate ( F(x) ) with respect to ( x ) to find ( F'(x) ), which will be the derivative of the given integral:
[ F'(x) = \frac{d}{dx} \left( \int_{3}^{x} e^{4t^2 - t} , dt \right) ]
This process involves calculating the antiderivative of ( f(t) ), then finding its derivative with respect to ( x ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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