How do you use the formula #A=1/2bh# to write a simplified expression for the area of a right triangle with leg lengths of #4xy^-1# and #7x^2#?

Answer 1

#A=(14x^3)/y#

#"Area of a triangle"=1/2 base xx height"#
If the base#=4xy^-1#
and the height#= 7x^2#
Then #A=1/2xx4xy^-1xx7x^2#
#:.A=14x^3y^-1#
#:.A=(14x^3)/y#
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Answer 2

The desired expression is #(14x^3)/y#

We are given that area of a right triangle is #1/2bh#, where #b# and #h# are legs of the triangle.
In the given case legs are #4xy^(-1)# and #7x^2#
hence are of right triangle is #1/2xx4xy^(-1)xx7x^2#
= #14x/yxx x^2#
= #(14x^3)/y#
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Answer 3

To find the area of a right triangle using the formula A = 1/2 * base * height, where the base (b) and height (h) are the lengths of the triangle's legs, you simply substitute the given values into the formula.

Given that the leg lengths are 4xy^(-1) and 7x^2, we can identify the base and height as follows:

Base (b) = 4xy^(-1) Height (h) = 7x^2

Now, we substitute these values into the formula:

A = 1/2 * (4xy^(-1)) * (7x^2)

To simplify, we multiply the terms:

A = 1/2 * 4 * 7 * x * x * y^(-1) * x^2

Which simplifies to:

A = 14x^(3) * y^(-1)

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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