How do you use the formula #A=1/2bh# to write a simplified expression for the area of a right triangle with leg lengths of #4xy^-1# and #7x^2#?
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The desired expression is
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To find the area of a right triangle using the formula A = 1/2 * base * height, where the base (b) and height (h) are the lengths of the triangle's legs, you simply substitute the given values into the formula.
Given that the leg lengths are 4xy^(-1) and 7x^2, we can identify the base and height as follows:
Base (b) = 4xy^(-1) Height (h) = 7x^2
Now, we substitute these values into the formula:
A = 1/2 * (4xy^(-1)) * (7x^2)
To simplify, we multiply the terms:
A = 1/2 * 4 * 7 * x * x * y^(-1) * x^2
Which simplifies to:
A = 14x^(3) * y^(-1)
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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