# How do you use the first and second derivatives to sketch #y= 3x^4 - 4x^3#?

See answer below

Find the second derivative and evaluate it at the critical values to find relative minimums or relative maximums:

To graph:

graph{3x^4-4x^3 [-5, 5, -5, 5]}

By signing up, you agree to our Terms of Service and Privacy Policy

- Find critical points by setting the first derivative equal to zero and solving for x.
- Determine the nature of each critical point using the second derivative test.
- Sketch the graph using the critical points and information about the concavity from the second derivative.

By signing up, you agree to our Terms of Service and Privacy Policy

- For what values of x is #f(x)= -x^3+3x^2-2x+2 # concave or convex?
- How do you determine whether the function #f^('')(x) = 36x^2-12# is concave up or concave down and its intervals?
- What are the points of inflection, if any, of #f(x)=x^(1/3) #?
- What is the second derivative of #f(x)= ln sqrt(3x-7)#?
- What are the points of inflection, if any, of #f(x)=2x^3 + 8x^2 #?

- 98% accuracy study help
- Covers math, physics, chemistry, biology, and more
- Step-by-step, in-depth guides
- Readily available 24/7