How do you use the distributive property to simplify #15(s-3)#?

Answer 1

Abigail Allen

#15s-45#

#"multiply each term in the parenthesis by 15"#

#rArrcolor(red)(15)(s-3)#

#=(color(red)(15)xxs)+(color(red)(15)xx-3)#

#=15s+(-45)=15s-45#

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Answer 2

Nathan Axel

To simplify (15(s-3)) using the distributive property, distribute the 15 across the terms inside the parentheses:

[15(s-3) = 15 \times s - 15 \times 3]

[= 15s - 45]

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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