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How do you use the difference of two squares formula to solve #4x^2=25#?

Answer 1

Isaiah Anthony

#f(x) = 4x^2 - 25 = (2x - 5)(2x + 5) = 0#

#(2x - 5) = 0 --> x = 5/2#

#(2x + 5) = 0 --> x = -5/2#

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Answer 2

Jameson Allen

To solve 4x^2 = 25 using the difference of two squares formula, you first rewrite the equation as (2x)^2 - 5^2 = 0. Then, you apply the formula (a^2 - b^2) = (a + b)(a - b), where a = 2x and b = 5. This gives you (2x + 5)(2x - 5) = 0. Finally, you solve each factor separately to find the values of x. So, either 2x + 5 = 0 or 2x - 5 = 0. Solve each equation for x to find the solutions.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.