How do you use the chain rule to differentiate #sqrt(-cosx)#?

Answer 1

#y'=sinx/(2sqrt(-cosx)#

#y= sqrt(-cosx)=(-cosx)^(1/2)#
#y'=1/2(-cosx)^(-1/2) *sinx#
#y'=sinx/(2sqrt(-cosx)#
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Answer 2

To differentiate sqrt(-cosx) using the chain rule, you first differentiate the outer function (sqrt) and then multiply by the derivative of the inner function (-cosx).

The derivative of sqrt(u) with respect to u is (1/2)*u^(-1/2), and the derivative of -cosx with respect to x is sinx.

So, applying the chain rule, the derivative of sqrt(-cosx) with respect to x is:

(1/2)*(-cosx)^(-1/2) * (-sinx)

= -sinx / (2 * sqrt(-cosx))

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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