How do you use synthetic substitution to find #P(2)# for the polynomial #P(x) = 2x^35x^2+x+2#?
Using synthetic division to find the value of a function at a value is a quick and easy manner to evaluate larger polynomials, and is often used in computer programs because of how it operates using simple multiplication and addition.
A note before continuing:
Leave a little vertical space (where you will write some numbers soon), and draw a horizontal line, much like you would if this were an addition problem.
Lastly, copy down the first number in the row you first wrote (2) and write it underneath the line:
From now on we will repeat two steps over and over until we run out of numbers to work with:
 Multiply the last number you wrote below the line by the number in "the box" (2 in our case), and write that answer just above the line underneath the next number to the right on the top row.
 Add the next number to the right on the top row to the number you just copied, and write the sum under the line.
For our problem, we take the last number we wrote under the line (2), and multiply it by the number in "the box" (2) to get a product of 4. We write that in the next space, which I've colored blue in the next picture.
We still have numbers in the top row to work with (1 and 2), so repeat these two steps: Multiply over, add down.
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To use synthetic substitution to find P(2) for the polynomial P(x) = 2x^3  5x^2 + x + 2, follow these steps:

Write down the coefficients of the polynomial in descending order of the powers of x. Coefficients: 2, 5, 1, 2

Replace x with the value you're evaluating the polynomial at (in this case, x = 2).

Perform synthetic substitution using the given value (x = 2) and the coefficients of the polynomial.

Follow the synthetic division process to compute the result.

The last number in the synthetic division table will give you the value of P(2).
Following these steps, you'll find P(2) for the given polynomial.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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