# How do you use substitution to integrate #x^3sqrt(x-3)#?

See the explanation.

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To integrate (x^3\sqrt{x-3}) using substitution, we can let (u = x - 3). Then, (du = dx). The integral becomes (\int (u + 3)^3\sqrt{u} , du). Now, we can expand ((u + 3)^3) using binomial expansion, and then integrate the resulting expression.

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