How do you Use Simpson's rule with #n=8# to approximate the integral #int_0^2root4(1+x^2)dx#?
The answer is 2.41223163.
For any numerical approximation of a function, you always start with a table of values. For your problem, we have:
#a=0#
#b=2#
#n=8#
So,
#Delta x=(b-a)/n=1/4#
#x_i=a+i Delta x, i in {0, 1, ..., 8}#
Now it is a matter of applying Simpson's Rule:
#int_0^2 (1+x^2)^(1/4)dx = int_0^2 f(x)dx ~~ (Delta x)/3(f(x_0)+4f(x_1)+2f(x_2)+4f(x_3)+...+2f(x_6)+4f(x_7)+f(x_8))#
I'll skip the substitution of values because it's messy.
We get 2.41223163 as the approximation.
Using numerical integration on a calculator gets a value of 2.412231919 which means the approximation is good to 6 decimal places.
Notice the pattern of the coefficients for the sum is: 1, 4, 2, 4, ..., 2, 4, 1. This means that to use Simpson's Rule, we need an odd number of values or an even number of intervals;
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To use Simpson's rule with ( n = 8 ) to approximate the integral ( \int_0^2 \sqrt{4(1+x^2)} , dx ), follow these steps:
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Divide the interval ([0, 2]) into ( n = 8 ) subintervals of equal width. The width of each subinterval, ( \Delta x ), is calculated as ( \frac{b - a}{n} ), where ( a = 0 ) and ( b = 2 ).
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Calculate the function values ( f(x_i) ) at each of the ( n+1 ) equally spaced points within the interval ([0, 2]).
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Apply Simpson's rule formula: [ \text{Approximate} = \frac{\Delta x}{3} \left[ f(x_0) + 4\sum_{i=1}^{n/2} f(x_{2i-1}) + 2\sum_{i=1}^{n/2-1} f(x_{2i}) + f(x_n) \right] ]
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Substitute the values into the formula and compute the approximate value of the integral.
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The result obtained from the calculation will be the approximation of the integral ( \int_0^2 \sqrt{4(1+x^2)} , dx ) using Simpson's rule with ( n = 8 ).
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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