# How do you use sigma notation to write the sum for #[1-(1/6)^2]+[1-(2/6)^2]+...+[1-(6/6)^2]#?

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To express the given sum using sigma notation, we can first observe the pattern in the terms:

[1 - \left(\frac{1}{6}\right)^2 + 1 - \left(\frac{2}{6}\right)^2 + \ldots + 1 - \left(\frac{6}{6}\right)^2]

Notice that the expression (1 - \left(\frac{k}{6}\right)^2) appears in each term, where (k) ranges from 1 to 6. We can express this pattern using sigma notation.

The sum can be represented as:

[\sum_{k=1}^{6} \left(1 - \left(\frac{k}{6}\right)^2\right)]

This notation represents the sum of the expression (1 - \left(\frac{k}{6}\right)^2) as (k) ranges from 1 to 6.

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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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