How do you use Heron's formula to find the area of a triangle with sides of lengths #19 #, #14 #, and #13 #?
The area of the triangle would be
￼
First we would find S which is the sum of the 3 sides divided by 2.
Then use Heron's Equation to calculate the area.
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To use Heron's formula to find the area of a triangle with sides of lengths 19, 14, and 13, follow these steps:

Calculate the semiperimeter of the triangle, denoted by ( s ), using the formula: [ s = \frac{a + b + c}{2} ] where ( a ), ( b ), and ( c ) are the lengths of the sides of the triangle.

Once you have ( s ), use Heron's formula to find the area (( A )) of the triangle: [ A = \sqrt{s(s  a)(s  b)(s  c)} ]

Substitute the values of ( a ), ( b ), and ( c ) into the formula and calculate the area.
For the given triangle with side lengths 19, 14, and 13: [ s = \frac{19 + 14 + 13}{2} = 23 ]
[ A = \sqrt{23(23  19)(23  14)(23  13)} ]
[ A = \sqrt{23(4)(9)(10)} ]
[ A = \sqrt{8280} ]
[ A \approx 90.95 ]
Therefore, the area of the triangle is approximately 90.95 square units.
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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