How do you use Heron's formula to find the area of a triangle with sides of lengths #3 #, #8 #, and #6 #?
The Area is
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First we would find S which is the sum of the 3 sides divided by 2.
Then use Heron's Equation to calculate the area.
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To use Heron's formula to find the area of a triangle with sides of lengths ( a = 3 ), ( b = 8 ), and ( c = 6 ), follow these steps:

Calculate the semiperimeter (( s )) of the triangle: ( s = \frac{a + b + c}{2} )

Compute the area (( A )) using Heron's formula: ( A = \sqrt{s \times (s  a) \times (s  b) \times (s  c)} )
Substitute the given side lengths into the formulas:

Calculate the semiperimeter: ( s = \frac{3 + 8 + 6}{2} = \frac{17}{2} )

Compute the area using Heron's formula: ( A = \sqrt{\frac{17}{2} \times \left(\frac{17}{2}  3\right) \times \left(\frac{17}{2}  8\right) \times \left(\frac{17}{2}  6\right)} ) ( A = \sqrt{\frac{17}{2} \times \frac{11}{2} \times \frac{1}{2} \times \frac{5}{2}} ) ( A = \sqrt{\frac{17 \times 11 \times 1 \times 5}{2 \times 2 \times 2 \times 2}} ) ( A = \sqrt{\frac{935}{8}} )
Therefore, the area of the triangle with side lengths 3, 8, and 6 using Heron's formula is ( \sqrt{\frac{935}{8}} ).
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When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a onesided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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