How do you use Heron's formula to find the area of a triangle with sides of lengths #11 #, #14 #, and #13 #?

Answer 1

#Area = 67.53 units^2 #

First we would find S which is the sum of the 3 sides divided by 2.

#S = (11 + 14 + 13)/2 # = #38/2# = 19

Then use Heron's Equation to calculate the area.

#Area = sqrt(S(S-A)(S-B)(S-C)) #

#Area = sqrt(19(19-11)(19-14)(19-13)) #

#Area = sqrt(19(8)(5)(6)) #

#Area = sqrt(4,560) #

#Area = 67.53 units^2 #

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Answer 2

To use Heron's formula to find the area of a triangle with sides of lengths 11, 14, and 13, you first calculate the semi-perimeter of the triangle, which is half the perimeter. Then, using Heron's formula, which states that the area ( A ) of a triangle with side lengths ( a ), ( b ), and ( c ) is given by:

[ A = \sqrt{s(s - a)(s - b)(s - c)} ]

where ( s ) is the semi-perimeter and ( a ), ( b ), and ( c ) are the lengths of the sides, you plug in the given side lengths to find the area of the triangle.

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Answer from HIX Tutor

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.

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