How do you use Heron's formula to find the area of a triangle with sides of lengths #12 #, #5 #, and #7 #?
The given numbers cannot be lengths of sides of a triangle. (The area is zero)
If we substitute given numbers we see, that:
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To use Heron's formula to find the area of a triangle with side lengths (a), (b), and (c), where (s) is the semi-perimeter calculated as (\frac{a + b + c}{2}):
[Area = \sqrt{s(s - a)(s - b)(s - c)}]
For the given triangle with side lengths (a = 12), (b = 5), and (c = 7):
[s = \frac{12 + 5 + 7}{2} = 12]
[Area = \sqrt{12(12 - 12)(12 - 5)(12 - 7)}]
[Area = \sqrt{12 \times 0 \times 7 \times 5}]
[Area = \sqrt{0}]
[Area = 0]
Therefore, the area of the triangle with side lengths 12, 5, and 7 is 0 square units. This indicates that the given side lengths do not form a valid triangle.
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When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
When evaluating a one-sided limit, you need to be careful when a quantity is approaching zero since its sign is different depending on which way it is approaching zero from. Let us look at some examples.
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